Question 665574
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ 2\ =\ 0]


has no real roots, the roots being *[tex \LARGE \pm{i}\sqrt{2}].  If the denominator of a rational function never goes to zero, then there are no vertical asymptotes.  Use your graphing calculator or a graphing program (Graph, available for free download at <a href="http://www.padowan.dk/">Padowan</a>) to get a picture of the function and see that there are no vertical asymptotes.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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