Question 665465
Let the smaller digit be x and the larger digit be y.  From the problem statement we are given that y = 3x.  
  
The two-digit number is 10x + y, and reversing the digits gives 10y + x.  We are told that reversing the digits doubles the original number, so

10y + x = 2(10x + y)
 
Substituting 3x for y into this equation gives:
  
10(3x) + x = 2(10x + 3x)
30x + x = 20x + 6x
31x = 26x
  
There are no non-zero values for x which make this equation true, so there is no solution to this problem as stated.