Question 500395
I think the original solver overlooked the fact that there are duplicated letters in the word that reduce the number of distinct permutations.  There are 2 I's and 3 M's, so the actual number of different ways to arrange the letters in MINIMUMS is {{{8!/(2!3!)}}} = (8*7*6*5*4*3*2*1)/((2*1)*(3*2*1)) = 3360}}}