<PRE><B>Question 665503</B>
&lt;pre&gt;
Here&#39;s a little more detail on how to analyze the English language
and translate it into the language of algebra:
&lt;/pre&gt;
Eight less than the product of eleven and a number

Eight less than the product of eleven and &lt;b&gt;&lt;u&gt;a number&lt;/b&gt;&lt;/u&gt;
&lt;pre&gt;
Replace the words &quot;&lt;b&gt;&lt;u&gt;a number&lt;/b&gt;&lt;/u&gt;&quot; by &quot;x&quot;.
&lt;/pre&gt;
Eight less than the product of eleven and x

&lt;u&gt;&lt;b&gt;Eight&lt;/u&gt;&lt;/b&gt; less than the product of &lt;b&gt;&lt;u&gt;eleven&lt;/b&gt;&lt;/u&gt; and x
&lt;pre&gt;
Replace the word &quot;&lt;b&gt;&lt;u&gt;Eight&lt;/b&gt;&lt;/u&gt;&quot; by &quot;8&quot; and the word &quot;&lt;b&gt;&lt;u&gt;eleven&lt;/b&gt;&lt;/u&gt;&quot; by 11:
&lt;/pre&gt;
8 less than the product of 11 and x

8 less than &lt;b&gt;&lt;u&gt;the product of 11 and x&lt;/b&gt;&lt;/u&gt;
&lt;pre&gt;
Replace the words &quot;&lt;b&gt;&lt;u&gt;the product of 11 and x&lt;/b&gt;&lt;/u&gt;&quot; by &quot;11x&quot;
&lt;/pre&gt;
8 less than 11x
&lt;pre&gt;
To make something 8 less than it is, you subtract 8 from it.
We want to make llx to be 8 less than it is, so we subtract 8
from it:
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11x - 8  
&lt;pre&gt;
--------------------------------------------------
&lt;/pre&gt; 
Ten times the difference between a number and Fifty. 

&lt;b&gt;&lt;u&gt;Ten&lt;/b&gt;&lt;/u&gt; times the difference between &lt;b&gt;&lt;u&gt;a number&lt;/b&gt;&lt;/u&gt; and &lt;b&gt;&lt;u&gt;Fifty&lt;/b&gt;&lt;/u&gt;.
&lt;pre&gt;
Replace the words &quot;&lt;b&gt;&lt;u&gt;a number&lt;/b&gt;&lt;/u&gt;&quot; by x, the word &quot;&lt;b&gt;&lt;u&gt;ten&lt;/b&gt;&lt;/u&gt;&quot; by 10, and &quot;&lt;b&gt;&lt;u&gt;fifty&lt;/b&gt;&lt;/u&gt;&quot; by &quot;50&quot;
&lt;/pre&gt;
10 times the difference between x and 50.

10 times &lt;b&gt;&lt;u&gt;the difference between x and 50&lt;/b&gt;&lt;/u&gt;.
&lt;pre&gt;
Replace the words &quot;&lt;b&gt;&lt;u&gt;the difference between x and 50&lt;/b&gt;&lt;/u&gt;&quot; by &quot;(x-50)&quot;
&lt;/pre&gt;
10 times (x-50)
&lt;pre&gt;
Replace that by
&lt;/pre&gt;
10(x-50)
&lt;pre&gt;
-----------------------
&lt;/pre&gt;
The product of 9 and the total of z and 4

The product of 9 and &lt;b&gt;&lt;u&gt;the total of z and 4&lt;/b&gt;&lt;/u&gt;
&lt;pre&gt;
To find a total of two things you put a plus between them, so
replace the words &quot;&lt;b&gt;&lt;u&gt;the total of z and 4&lt;/b&gt;&lt;/u&gt;&quot; by &quot;(z+4)&quot;
&lt;/pre&gt;
The product of 9 and (z+4)
&lt;pre&gt;
Replace that by
&lt;/pre&gt;
9(z+4)&lt;pre&gt;

Edwin&lt;/pre&gt;</PRE>