Question 665445
(x,-6) (1,2) 

d=	{{{sqrt((y2-y1)^2+(x2-x1)^2)}}}	

	
17 = {{{sqrt((2-(-6))^2+(1-x)^2)}}}	

17= {{{sqrt((8)^2+(1-2x+x^2))}}}

square both sides

17^2= 8^2+1-2x+x^2	

x^2-2x+64+1-289=0

x^2-2x-224=0

x^2-16x+14x-224=0

x(x-16)+14(x-16)=0
(x-16)(x+14)=0

x=16 OR -14

(16,-6) (-14,-6)