Question 60247
{{{(5-i)/(3-2i)}}}  Multiply the numerator and the denominator by the conjugate of the denominator: (3+2i)
{{{(5-i)(3+2i)/((3-2i)(3+2i))}}}
{{{(5(3+2i)-i(3+2i))/(3(3+2i)-2i(3+2i))}}}
{{{(15+10i-3i-2i^2)/(9+6i-6i-4i^2)}}}  (i^2=-1)
{{{(15+7i-2(-1))/(9-4(-1))}}}
{{{(15+7i+2)/(9+4)}}}
{{{(17+7i)/13}}}
{{{highlight(17/13+(7/3)i)}}}  <---standard form a+bi
Happy Calculating!!!