Question 664143
Just in case you yet need understanding or the solution...
Using the coordinates (-2,3) and (0,1) you can find the slope
slope = {{{(1-3)/0-(-2)) = (-2)/(2)}}}
The slope is {{{-(2/2)}}}
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y=mx+b
Using the coordinate (-2,3), plug in x and y to solve for b
3 = {{{-(2/cross(2))*cross(-2)}}} + b
3 = 2 + b
b = 3-2 = 1
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Therefore, the linear equation is 
y = {{{-3/2}}}x + 1
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Confirm this using the other coordinate (0,1)
1 = {{{(-3/2)*0}}} + b
b = 1
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{{{graph(300,200,-10,10,-10,10,(-3/2)x+1)}}}