Question 665136
{{{5x^2/6-7x/2+2/3=0}}} ....each term on both sides multiply by {{{6}}}


{{{6*5x^2/6-6*7x/2+6*2/3=6*0}}}


{{{cross(6)*5x^2/cross(6)-cross(6)3*7x/cross(2)+cross(6)2*2/cross(3)=0}}}



{{{5x^2-21x+4=0}}}......now use quadratic formula to solve for {{{x}}}


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


{{{x = (-(-21) +- sqrt( (-21)^2-4*5*4 ))/(2*5) }}}


{{{x = (21 +- sqrt( 441-80 ))/10 }}}


{{{x = (21 +- sqrt( 361 ))/10 }}}


{{{x = (21 +- 19)/10 }}}


solutions:


{{{x = (21 + 19)/10 }}}

{{{x = 40/10 }}}

{{{highlight(x = 4)}}}

or

{{{x = (21 - 19)/10 }}}

{{{x = -2/10 }}}

{{{highlight(x = -0.2)}}}