Question 664702
 {{{sqrt(96)}}} - {{{sqrt(6)}}}
Factor inside the 1st radical to reveal a perfect square
{{{sqrt(16*6)}}} - {{{sqrt(6)}}}
Extract the square root of 16
{{{4*sqrt(6)}}} - {{{sqrt(6)}}} = {{{3*sqrt(6)}}}
now we have like terms, just do the math.
 (a 1 is understood to be before the 2nd radical)