Question 664700
 Find two consecutive positive even integers such that the square of the smaller is 4 more than 4 times the larger."
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Two consecutive even integers: x, (x+2)
:
The equation for what it says, the word "is" usually means "="
x^2 = 4(x+2) + 4
x^2 = 4x + 8 + 4
x^2 = 4x + 12
Arrange as a quadratic equation
x^2 - 4x - 12 = 0
Factors to
(x-6)(x+2) = 0
Only the positive integer is required
x = 6, and 8 are the two integers
:
:
See if that works
6^2 = 4(8) + 4
36 = 32 + 4; confirms our solution