<PRE><B>Question 664662</B>
ou have 10 liters of a solution that is 30% alcohol, how many liters of a 80% alcohol solution must you add to obtain a solution that is 50% alcohol?
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Eqution:
alcohol + alcohol = alcohol
0.30*10 + 0.80x = 0.50(10+x)
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30*10 + 80x = 50*10 + 50x
30x = 20*10
x = 6 2/3 liters (amt. of 80% solution needed)
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Cheers,
Stan H.</PRE>