Question 664451
use the standard equation that has the form

{{{(x - h)^2 + (y - k)^2 = r^2}}} where {{{h}}} and {{{k}}} are the {{{x}}}- and {{{y}}}-coordinates of the {{{center}}} of the circle and {{{r}}} is the radius


you are given:


{{{(x-5)^2 + (y+6)^2 = 49}}}

so, {{{h=5}}}, {{{k=-6}}}, and {{{r=7}}}

	

{{{drawing( 600, 600, -10, 15, -15, 10, 
         grid(1),circle(5,-6,0.2),
         blue( circle( 5, -6, 7, 1 ) )
           
)}}}