Question 60208
|(3,1),(2,5),(4,0),(3,-2)|
I don't know what your directions are, but if you're being asked if this relation is a function, it's not.
You can't have two diffent y's for the same x.
(3,1) and (3,-2)  have the same x=3, but different y's=1,-2
I hope that's what you needed.
Happy Calculating!!!