Question 60195
Hi Sher,

  Solve the system by addition:

E1:  5x - 3y = 13
E2:  4x - 3y = 11
:
 Multiply E2 by -1 and add E1+E2 and the y's will be eliminated so that you can solve for x.
:
E2:  -1(4x-3y)=-1(11)----> -4x+3y=-11
:
5x-3y=13
-4x+3y=-11
__________
x+0=2
x=2
Substitute x=2 into either equation and solve for y.
5(2)-3y=13
10-3y=13
-10+10-3y=-10+13
-3y=3
-3y/-3=3/-3
y=-1
The solution is: (x,y)=(2,-1)
Happy Calculating, Sher!!!