Question 301900
I think this problem can be simplified further.
{{{y^2 + 7y - 18}}} can be factored into {{{(y + 9)*(y - 2)}}}
{{{y^2 + 2y - 63}}} can be factored into {{{(y + 9)*(y - 7)}}}
So...
{{{(y^2 + 7y - 18)/(y^2 + 2y - 63) = ((y + 9)(y - 2)) / ((y + 9)(y - 7)) = (y-2)/(y-7)}}}