Question 663973
Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(16)+-sqrt((16)^2-4(5)(12)))/(2(5))}}}


{{{x = (-16+-sqrt(256-(240)))/(10)}}}


{{{x = (-16+-sqrt(16))/10}}}


{{{x = (-16+sqrt(16))/10}}} or {{{x = (-16-sqrt(16))/10}}}


{{{x = (-16+4)/10}}} or {{{x = (-16-4)/10}}}


{{{x = -12/10}}} or {{{x = -20/10}}}


{{{x = -6/5}}}    or    {{{x = -2}}}