Question 663947
a linear equation in {{{slope-intercept form is {{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is {{{y-intercept}}}


you have {{{2x=y }}} or {{{y=2x}}}

if you compare it to  {{{y=mx+b}}}, you see that {{{m=2}}} and {{{b=0}}} which means you have a line that crosses {y-axis}}} at {{{0}}} and has positive slope, so its graph goes through I and III quadrant and line is raising

since you already have one point to plot on a coordinate system, and it is ({{{0}}},{{{0}}}), we need one more point to graph the line

let {{{x=1}}}...=>...{{{y=2*1=2}}}; so, second point will be ({{{1}}},{{{2}}})

now we can graph it

{{{drawing(600,600,-10,10,-10,10,grid(1),circle(1,2,0.2),graph(600,600,-10,10,-10,10,2x))}}}