Question 663895
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Hi,
h(t)={{{ -16t^2 +64t+400 = -16(t -2)^2 + 64 + 400 = -16(t-2)^2 + 464}}}
h(t) = {{{-16(t-2)^2 + 464}}}  V(2,464)max,   464ft is the max height.
 0 = -16(t-2)^2 + 464
(t-2)^2 = 29
 t = 2 ± sqrt(29) ||tossing out negative solution for unit measrure
 t = 7.39 sec, time it takes to hit the ground  

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