Question 663846


given: 
{{{ f(x)= x^2-7 }}} and 

{{{ g(x)= x+3 }}} 

find:{{{ (f-g)(t+2)}}}

first write {{{f(x)-g(x)}}}

{{{f(x)-g(x)=x^2-7-(x+3)}}}

{{{f(x)-g(x)=x^2-7-x-3}}}

{{{f(x)-g(x)=x^2-x-10}}}.....now replace each {{{x}}} with {{{t+2}}}


{{{f-g(t+2)=(t+2)^2-(t+2)-10}}}

{{{f-g(t+2)=t^2+4t+4-t-2-10}}}

{{{f-g(t+2)=t^2+3t+4-12}}}

{{{f-g(t+2)=t^2+3t-8}}}