Question 663811

to find the slope {{{m}}} and {{{y}}} intercept, first write your equations in {{{ slope-intercept}}} form: {{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is {{{y-intercept}}} 

1.

{{{-3-12y=4x }}}
{{{-3-4x=12y }}}
{{{-3/12-(4/12)x=y }}}

{{{-1/4-(1/3)x=y }}} or

{{{y=-(1/3)x-1/4}}}

so,{{{m=-(1/3)}}} and {{{b=-1/4}}}

 {{{ graph( 600, 600, -10, 10, -10, 10, -(1/3)x-1/4) }}} 


2.

{{{5y+25=4x}}}

{{{5y=4x-25}}}

{{{y=(4/5)x-25/5}}}

{{{y=(4/5)x-5}}}

here,{{{m=(4/5)}}} and {{{b=-5}}}


 {{{ graph( 600, 600, -10, 10, -10, 10,(4/5)x-5) }}}

3.

{{{6y-3=38x}}}

{{{y=(38/6)x+3/6}}}

{{{y=(6.33)x+1/2}}}

here,{{{m=6.33}}} and {{{b=1/2=0.5}}}

{{{ graph( 600, 600, -10, 10, -10, 10,(6.33)x+1/2) }}}

4.

{{{(1/2)x+(3/2)y=1}}}

{{{(3/2)y=-(1/2)x+1}}}...both sides multiply by {{{2}}}

{{{2(3/2)y=-(1/2)2x+1*2}}}

{{{3y=-1x+2}}}

{{{y=-(1/3)x+2/3}}}

and here,{{{m=-(1/3)}}} and {{{b=2/3}}}


{{{ graph( 600, 600, -10, 10, -10, 10,-(1/3)x+2/3) }}}