Question 663733
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Hi,
90% confidence Interval z(&#945;/2) = 1.65   and SD = 20
ME = 1.65(20/sqrt(n)
sqrt(n) = 1.65*20/.04 = 825 , n^2 = 380,625

ME = 1.65*20/sqrt(400) = 1.65
(C) What happens to the Maximum Error of Estimate as the sample size gets larger? ME  gets smaller

 (D) What effect does the answer to C above have to the size of the confidence interval? gets smaller as well

  mean - ME < {{{mu}}} < mean + ME

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