Question 663703
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
find two consecutive odd numbers{{{highlight(x)}}}and{{{highlight(x+2)}}} whose square of the larger number 
<u>is</u> 208 more than nine times the smaller number
Translating into an equation***
 (x+2)^2 = 9x + 208
x^2 + 4x + 4 = 9x + 208
 x^2 - 5x - 204 = 0   ||factor or use the Quadratic formula {{{x = (5 +- sqrt( 841 ))/(2) }}}
(x-17)(x+12) = 0 , x = 17  (throwing out negative even number -12)
 The two consecutive odd numbers are  17, 19
and...
 {{{19^2 = 9*17 + 208= 361}}} 

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