Question 663685
recall: complementary angles add up to {{{90}}} degrees

{{{A+B=90}}}

B=(x=29),angle {{{A=3x-3}}}

I guess you made mistake with B=(x=29); I assume it should be {{{B=(x+29)}}}

if so, then 

{{{x+29+3x-3=90}}}

{{{26+4x=90}}}

{{{4x=90-26}}}

{{{4x=64}}}

{{{x=16}}}


{{{A=3x-3}}}

{{{A=3*16-3}}}

{{{A=48-3}}}

{{{highlight(A=45)}}}


{{{B=16+29}}}
{{{highlight(B=45)}}}

but, in case you have {{{highlight(B=29)}}} and {{{A=3x-3}}}, then

{{{3x-3+29=90}}}

{{{3x+26=90}}}

{{{3x=90-26}}}

{{{highlight(3x=64)}}}



{{{A=3x-3}}}

{{{A=64-3}}}

{{{highlight(A=61)}}}