Question 663608
x=y/2+6 and x=y^2

Graphically plot points for both graphs and locate the intesection

x=y/2+6

x= 0 , y= y=-12  (0,-12)
x=6 , y=0(6,0)

 and x=y^2

x=0, y=0  (0,0)
x=1,y=1 (1,1)
x=4 , y= +/-2  (4,-2) (4,2)
x=9, y=+/-3  (9,3) (9,-3)

{{{drawing(300,300,-10,15,-10,10,circle(0,-12,0.3),circle(6,0,0.3),circle(4,-2,0.3),circle(4,2,0.3),circle(9,3,0.3),circle(9,-3,0.3),circle(7.34,2.71,0.3),grid(1),graph(300,300,-10,15,-10,10,y=2x-12,y=sqrt(x),y=-sqrt(x)))}}}

The intersection in the first quadrant is the solution. (7.34,2.71)