Question 663414
a father is three times as old as his son. after twelve years, his age will be twice as that of his son then. find their present ages.
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Equations:
f = 3s
f+12 = 2(s+12)
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Substitute for "f" and solve for "s":
3s+12 = 2s+24
s = 12 yrs (the son's age)
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Solve for "f":
f = 3s
f = 3*12 = 36 yrs (the father's age)
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Cheers,
Stan H.
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