Question 663336
x^2 + kx + 10
multiples of 10
1,10 where k would be 10+1 = 11
(x+1)(x+10) = x^2 + 10x + 1x + 10 = x^2 + 11x + 10
-1,-10 where k would be -10+-1=-11
(x-1)(x-10) = x^2 - 10x - 1x + 10 = x^2 - 11x + 10
2,5 where k would be 5+2 = 7
(x+2)(x+5) = x^2 + 2x + 5x + 10 = x^2 + 7x + 10
-2+-5 where k would be -5+-2=-7
(x-2)(x-5) = x^2 - 2x - 5x + 10 = x^2 - 7x + 10
k could equal -7, 7, -11 or 11