Question 60103
The given set of equations are: 


{{{7y^2 + 6}}} = {{{y^2}}}


Subtracting 6 + {{{y^2}}} from both sides of the above equation, we get: 


{{{7y^2 - y^2}}} = - 6 



{{{6y^2 }}} = - 6



Hence, {{{ y^2 }}} = -1 


Therefore y = + or - i rs(1)  


where rs stands for radical


{{{x^2 - 1}}} = -16


adding 1 to both sides, we get:


{{{x^2}}} = - 15



Taking squae root, we get



x = + or - i rs(15)