<PRE><B>Question 662858</B>
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AC congruent CE by defn midpoint, BC congruent CD given, AD = AC + CD and BE = BC + CE by the partition postulate, AC + CD = AC + BC by substitution, AC + BC = BC + CE by substitution, AC + CD = BC + CE by transitive equality, therefore AD = BE by substitution, Q.E.D.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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