Question 662746
<pre>
1     1    -1     0
3    -1     3    -2
1     2    -3    -1


1     1    -1     0
0    -4     6    -2    R2 - 3R1
1     2    -3    -1



1     1    -1     0
0    -4     6    -2
0     1    -2    -1   R3 - R1


1    1   -1     0
0    1   -1.5   0.5  (1/4)*R2
0    1   -2     1


1    1   -1      0
0    1   -1.5    0.5
0    0   -0.5   -1.5   R3 - R2


1    1   -1      0
0    1   -1.5    0.5
0    0    1      3    -2*R3


1    1   -1      0
0    1   -1.5    0.5
0    0    1      3    -2*R3


1     1    -1     0
0     1     0     5   R2 + 1.5*R3
0     0     1     3


1     1     0     3   R1 + R3
0     1     0     5
0     0     1     3


1     0     0    -2   R1 - R2
0     1     0     5
0     0     1     3
</pre>

So x = -2, y = 5 and z = 3