<PRE><B>Question 662732</B>
 Given a level of confidence of 95% and a population standard deviation of 9, answer the following:
(A) What other information is necessary to find the sample size (n)?
n = [z*s/E]^2
You need to know the maximum allowed error.
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(B) Find the Maximum Error of Estimate (E) if n=72. Show all work.
ME = z*s/sqrt(n) = 1.96*9/sqrt(72) = 2.08
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Cheers,
Stan H.
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