Question 662660
x+y=7
3x^2 + 2y^2 = 59
3(-y+7)(-y+7) + 2y^2 = 59
3(y^2-7y-7y+49) + 2y^2 = 59
3y^2 - 42y + 147 + 2y^2 = 59
5y^2 - 42y + 88 = 0
(5y-22)(y-4) = 0
5y-22=0 so y = 22/5
y-4=0 so y = 4
Two possibilities
if y = 4, x = 7-4=3
if y = 22/5, x = 7 - 22/5 = 13/5
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