Question 662623
let numerator be x
denominator = x+1

Numerator doubled = 2x
denominator = x+1

{{{(x/(x+1)) + (2x/(x+1)) =2}}}

LCD = (x+1)

{{{3x/(x+1)}}} = 2

3x=2(x+1)
3x=2x+2
3x-2x=1
x=2
denominator = x+1 = 1+2 =3
The fraction is 2/3

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