Question 662523
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{|m|}{5}\ =\ 3]


Multiply both sides by 5


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ |m|\ =\ 15]


Apply the definition of absolute value:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ |x|\ =\ \left\{\ \ x\text{ if }x\ \geq\ 0\cr-x\text{ if }x\ <\ \,0\right]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m\ =\ 15]


or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m\ =\ -15]


Which is to say the solution set is *[tex \LARGE \left\{-15,\,15\right\}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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