Question 662514
Find the smallest positive number x, so that sin(x^2+3x+1)=-1?
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sin(x^2+3x+1)=-1
(x^2+3x+1) = 3pi/2 or -pi/2
{{{x^2+3x+1 = 3pi/2}}}
{{{x^2 + 3x + 1 - 3pi/2 = 0}}}
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Or,
{{{x^2 + 3x + 1 + pi/2 = 0}}}
Solve for x