Question 662487
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Hi,
Re TY, yes, a bit of 'problem' here :)
might consider the following..idea being... if one of the Kings is a diamond...
then a different-suited, non-king card needs to be introduced for the remaining card

Five cards are chosen from a standard deck of 52.
P(3K & '2D')= P(No K(D) & 2Ds) + P(One K is a D) = 
              {{{((3C3*12C2) + (3C2*1C1*12C1*36C1))/(52C5)}}}= 
              {{{(66 + 1296)/2598960 = 1362/2598960 = .000524}}}