Question 60017
Please show me how to plug in the points for Y on these equations.  I made up points for X:   

equations Y = 2X - 4 (0, 3, 4)

equation  y = -2/3X + 4 (0, 3, 4)

You don't plug in points for y if you plug in points for x, you let x = the numbers you chose and solve for y.
y=2x-4
If x=0
y=2(0)-4
y=0-4
y=-4
(0,-4)  is a point on the line.
If x=3
y=2(3)-4
y=6-4
y=2
(3,2) is a point on the line.
If x=4
y=2(4)-4
y=8-4
y=4
(4,4) is a point on the line.
:
For {{{y=(-2/3)x+4}}}  Pick numbers that are divisible by 3, so that you don't have to add fractions.
for x=0
{{{y=(-2/3)(0)+4}}}
{{{y=0+4}}}
y=4
(0,4) is a point on the line.
for x=3
{{{y=(-2/3)(3)+4}}}
{{{y=-6/3+4}}}
{{{y=-2+4}}}
{{{y=2}}}
The point (3,2) is part of the line.
Don't choose 4, choose something like -3 for x
{{{y=(-2/3)(-3)+4}}}
{{{y=6/3+4}}}
{{{y=2+4}}}
{{{y=6}}}
(-3,6) is a point on the line.
Notice that both line contain the point (3,2).  If you graphed these two lines on the same graph, they would cross at (3,2)
{{{graph(300,200,-10,10,-10,10,2x-4,(-2/3)x+4)}}}
For fun, try to figure out which line goes to which equation.
Happy Calculating!!!