Question 662334
given the line is parallel to 3x+4y=4
so,slope of line=slope of 3x+4y=4 = -3/4
and the line is passing through (-4,2)
Hence the equation is y-2=-3/4(x-(-4))
                      4(y-2)=-3(x+4)
                       4y-8=3x+12
                      3x-4y+12+8=0
                      3x-4y+20=0 is the equation of line.