Question 662286
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Hi,
&#956; = 63% and  &#963; = 12%  
Find the smallest interval about the mean that contains at least 82% of the scores
(100-82)/2 = 18/2 = 9% on either side
z = 1.341
 1.341 = (x-63)/12
 1.341*12 + 63 = 79
 79-63 = 13
 82% of the scores will be between 50%-79%