Question 662284
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Hi,
{{{(x+2) / (x^2-9) + (x-3) / (x^2-2x-3) = (2x-3)/(x^2+4x+3)}}}
{{{(x+2) / (x^2-9) + (x-3) / ((x-3)(x+1)) = (2x-3)/(x^2+4x+3)}}}
{{{(x+2) / ((x-3)(x+3)) + 1 /(x+1) = (2x-3)/((x+3)(x+1)) }}}
|Multiplying thru by (x-3)(x+3)(x+1) so as all denominators = 1
 (x+2)(x+1) + (x-3)(x+3)= (2x-3)(x-3)
x^2 + 3x + 2 + x^2 - 9 = 2x^2-9x + 9
Will let you take it from here...