Question 662280

{{{4x + y = 25}}}........1
{{{3x + 4y= 22}}}.........2
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{{{4x + y = 25}}}........1..solve for {{{y}}}

{{{y = 25-4x}}}.........substitute in 2


{{{3x + 4(25-4x)= 22}}}.........2..solve for {{{x}}}

{{{3x + 100-16x= 22}}}

{{{ 100-13x= 22}}}


{{{ 100-22= 13x}}}


{{{ 78= 13x}}}


{{{ 78/13= x}}}

{{{  highlight(x=6)}}}

now find {{{y}}}


{{{y = 25-4x}}}

{{{y = 25-4*6}}}

{{{y = 25-24}}}

{{{highlight(y =1)}}}