Question 661926

{{{F=(7/4)(n-37) }}}...set {{{F=0}}} to solve for {{{n}}}


{{{0=(7/4)(n-37) }}}


{{{0=(7/4)n-(7/4)37) }}}


{{{0=(7n/4)-(7*37/4)) }}}....both sides multiply by {{{4}}}


{{{0*4=(7n/4)*4-(7*37/4)*4)) }}}


{{{0=7n-7*37 }}}


{{{7*37=7n }}}


{{{7*37/7=n }}}


{{{cross(7)*37/cross(7)=n }}}


{{{highlight(37=n) }}}