Question 661651
Simplify the expression. 
tan(sin^-1 (x))
(sin^-1 (x)) is an angle whose sin=x/1=opposite side/hypotenuse
by the pythagorean theorem
adjacent side=sqrt of (hypotenuse^2-opp side^2)=√(1^2-x^2)=√(1-x^2)
tan(sin^-1 (x))=opposite side/adjacent side=x/√(1-x^2)
tan(sin^-1 (x))=x/√(1-x^2)