Question 59977
solve the equation

{{{sqrt(x)=-1}}}
{{{(sqrt(x))^2=(-1)^2}}}
{{{x=1}}}  But you must check for extraneous solutions.
{{{sqrt(1)=-1}}}
{{{1=-1}}}  1 does not =-1, so x=1 is extraneous and there is no solution.
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Note:
Look at your problem:
{{{sqrt(x)=-1}}}
Can you take the square root of any number and get a negative answer.  No.
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Happy Calculating!!!