Question 661703
product where
x = hundreds
y = tens
z = ones
x=z
y=x+z = z+z=2z
Substituting into expanded form of a 3 digit number
100(x) + 10(y) + 1(z) = 3 digit number
100(z)+10(2z)+z
100z + 20z + z = 121z
recognizing that 121 fits the description
n^2 = 121
n = 11