Question 661445
if mr brown leaves 3.5 hours before ms brown and mr brown travels at 65 mph while ms brown travels at 90 mph how long before ms brown overtakes mr brown? 
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Mr. Brown DATA:
rate = 65 mph ; time = x hrs ; distance = 65x miles
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Ms. Brown DATA:
rate = 90 mph ; time = x-3 hrs ; distance = 90(x-3) miles
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Equation:
65x = 90(x-3)
65x = 90x - 270
25x = 270
x = 10.8 hrs = 10 hrs 48 minutes
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Cheers,
Stan H.