Question 661268
It turns out that the square with a certain perimeter has 
the maximum are
{{{ 184/4 = 46 }}} is the side of the square with perimeter
of 184
{{{ 46^2 = 2116 }}} is the area of the square
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To prove this is the maximum area, make the square
slightly rectangular
{{{ 47 + 47 + 45 + 45 = 184 }}} is slightly rectangular
{{{ 47*45 = 2115 }}} this area is less than the square