Question 661089
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Hi,
{{{x-4sqrt(x) = 32}}}   Let s^2 = x
 s^2 - 4s - 32 = 0
(s - 8)(s+4) = 0
(s+4) = 0 , s = -4, s^2 = x = 16  |||tossing out as an extraneous solution
0r
(s - 8) = 0 , s= 8 and s^2 = {{{x = 64}}}