Question 660985
Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(11)+-sqrt((11)^2-4(6)(-7)))/(2(6))}}}


{{{x = (-11+-sqrt(121-(-168)))/(12)}}}


{{{x = (-11+-sqrt(121+168))/(12)}}}


{{{x = (-11+-sqrt(289))/12}}}


{{{x = (-11+sqrt(289))/12}}} or {{{x = (-11-sqrt(289))/12}}}


{{{x = (-11+17)/12}}} or {{{x = (-11-17)/12}}}


{{{x = 6/12}}} or {{{x = -28/12}}}


{{{x = 1/2}}}    or    {{{x = -7/3}}}