Question 660871
1  the area of a triangle is {{{A=(1/2)b*h}}} 
if the base is doubled ({{{2b}}}) and the height is cut in half ({{{h/2}}}), we have 
{{{A=(1/2)(2b*h/2)}}} 

{{{A=(1/2)(cross(2)b*h/cross(2))}}} 

{{{A=(1/2)(b*h)}}} .....the area ..{{{highlight(remains_same)}}}

let {{{b=7}}} and {{{h=4}}}, then area is


{{{A=(1/2)7*4}}}

{{{A=(1/2)28}}}

{{{A=28/2}}}

{{{A=14}}}


if the base is doubled ({{{2*7=14}}}) and the height is cut in half ({{{4/2=2}}}), we have 

{{{A=(1/2)(14*2)}}

{{{A=(1/2)28}}

{{{A=28/2}}}

{{{A=14}}}..the area {{{highlight(remains_same)}}}


2 
if the base is doubled ({{{2b}}}) and the height remains the same ({{{h}}}), we have 

{{{A=(1/2)(2b*h)}}} 


{{{A=(1/cross(2))(cross(2)b*h)}}} 


{{{A=b*h}}} ............the area {{{highlight(doubles)}}}


example: let {{{b=7}}} and {{{h=4}}}, as above


if the base is doubled ({{{2*7=14}}}) and the height remains sam ({{{4}}}), we have 

{{{A=(1/2)(14*4)}}

{{{A=(1/2)56}}

{{{A=56/2}}}

{{{A=28}}}.......the area {{{highlight(doubles)}}}