Question 660836
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Hi, there--

Problem:
Graph {{{y=sqrt(x+2)}}} and give the domain and range.

Answer:
Your domain and range are correct.

The graph of {{{y=sqrt(x+2)}}} looks exactly like the graph of {{{y=sqrt(x)}}} except it is shifted 2 units to the left.

The graph looks a little like a half a parabola laying on its side (opening to the right.) The 
graph of your equation intersects the x-axis at (-2,0).

To get a sketch of the graph, make a quick (x,y) table:

x      y
-2    0
-1    1
2      2
7      3
14    4

Remember that x&#8805;2, and y&#8805;0.

You can see a picture of the graph if you google "graph y=sqrt(x+2)" (Don't include quotation 
marks.)

Hope this helps! Feel free to email, if you still have questions.

Mrs.Figgy
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